1. The Mean Value Theorem works :In the equation f(x)=x^2 works in the Theorem in [0,2]
-*****It is both continuous and differentiable within that interval.
f(0)= 2 and f(2)=4, the MVT guarentees a point c in the interval.
f'(c) = f(2)-f(0)/2-0
2c = 4-0/2 = 2
c=1
2. The Mean Value Theorem only works for continuous and differentiable functions. When there are gaps, or when non-differentiable, as in the case of f(x) = sqareroot(x^2) + 3.
-This graph has a corner at x=0
-Non-differentiable
-There could not be any tangent lines throughout the graph.
Haha. I like your notes on your pictures. A great idea.
ReplyDeleteYou know how you said the MVT guarantees a c on that interval? Guarantees a c that WHAT though? Can you be more specific? You're missing a very key word in all of this.
Also, I think you're just restating that non differentiable and discontinuous functions are a problem, but you're not stating why. Give examples, it's easier.
Details ?!
ReplyDeleteThis leaves me guessing...
hahahaha i like how you put your explanation in should i say bullet points??
ReplyDeletehahah and the notation on the graph.. hahahaha you know paint has this tool where you can type right???
hahahaha
but very catchy
ReplyDeleteNice writing, Hernandez! LOL jkk,
ReplyDeleteYes PLEASE take Wendy's advice,, hahah
I think you should explain what the mean value theorem is first and then continue on from there (:
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I like your "bullet points" also!